ALLISTARSymmetric Field Physics

Allistar Center · Geometry Atlas · Study

Space-Time Cones

Two interpenetrating copper coils, sealed inside a copper tetrahedron that fits them exactly. One version is proportioned by the golden ratio, the other by the square root of two.

Two copper tetrahedra side by side, each cut open at the front to show a double-cone copper coil inside. Left: V1, golden ratio. Right: V2, square root of two.

The idea

The starting point is a design principle: the double-cone coil must sit inside a perfectly fitting three-sided pyramid, a regular tetrahedron. If that is true, there should be a mathematical relationship between the cones, the tetrahedron, and the crystal at the centre. This page records the model, and everything the geometry shows when it is worked out exactly.

Each version has two cones on the same axis, one pointing up and one pointing down. The apex of each cone sits at the centre of the other cone's base. A single enamelled copper wire winds up the first cone, crosses to the second, winds down it, and returns to the start, so it forms a closed circuit.

Watch the video

Video coming soon

Chapters
  1. 0:00 Two cones in a tetrahedron
  2. 0:34 The build
  3. 0:56 Golden in two directions
  4. 1:35 Three motions
  5. 3:50 The fit, in 3D
  6. 4:34 Two numbers
  7. 5:10 The near-miss
  8. 5:36 The empty space
  9. 6:02 Tuning: φ to √2, and the fractal
  10. 7:12 Two paths

V1 and V2 side by side

V1: copper tetrahedron cut open, showing the golden-ratio double-cone coil, the core disc, and cyan reference lines from each face centre to the tetrahedron's centre.
V1 · Golden φCone height = φ × base diameter. The cyan lines run from the centre of each face to the tetrahedron's centre.
V2: copper tetrahedron cut open, showing the shorter √2 double-cone coil and the same core.
V2 · √2Cone height = √2 × base diameter. The crystal sits at the tetrahedron's centre.

Specifications

V1 · φV2 · √2
Cone base diameter D37 cm37 cm
Cone height Hφ·D = 59.87 cm√2·D = 52.33 cm
Cone apex angle34.34°38.94°
Turns per cone · wire333 · 0.8 mm enamelled Cu333 · 0.8 mm enamelled Cu
Turn spacing along the cone surface1.88 mm (1.08 mm gap)1.67 mm (0.87 mm gap)
Total wire · DC resistance≈ 388 m · ≈ 13.3 Ω≈ 388 m · ≈ 13.3 Ω
Tetrahedron edge (inside)137.8 cm128.5 cm
Tetrahedron height (inside)112.5 cm105.0 cm
Tetrahedron wall1 mm copper sheet1 mm copper sheet
Crystal height above the floor
(where the two coils cross)
29.93 cm26.16 cm
Tetrahedron centre above the floor28.05 cm26.16 cm
Gap between the two centres1.89 cm (crystal higher)0 (they coincide)

Tetrahedron sizes include the wire thickness; heights and the gap are exact values for the ideal geometry. "Fits exactly" means the lower base ring rests on the floor and the upper base ring touches all three sloping walls at once.

What the geometry shows

Worked out exactly, every dimension of the tetrahedron is the base diameter D multiplied by just two numbers: √2, which belongs to the tetrahedron, and the cone's own height ratio.

Explore it in 3D

Drag to rotate, scroll or pinch to zoom. Switch between the 78°, √2 and golden cones to watch the crystal move around the true centre, and meet it only with √2.

Turn on Cutting plane and press Side cut: the flat diagrams below are this slice. It passes through one corner and the middle of the opposite face, which is why the cut looks lopsided even though the tetrahedron is perfectly regular. The coil is drawn with fewer turns so it stays readable.

19.47° 17.17° touch crystal tetra centre 1.89 cm lower H = φ·D59.9 cm √2·D52.3 cm D = 37 cm V1 · Golden φ apex 34.34° · height (√2+φ)·D
The crystal sits 1.89 cm above the tetrahedron's true centre.
19.47° 19.47° touch crystal = tetra centre H = √2·D52.3 cm √2·D52.3 cm D = 37 cm V2 · √2 apex 38.94° · height 2√2·D
The crystal sits exactly at the centre, and the coil height equals the headroom above it.
Coil windings Crystal Tetrahedron centre Centre to face (90°) Ring touches the wall

Both panels are drawn to the same scale. Each is a cut through the axis, one base corner (left) and the middle of the opposite base edge (right).

Exact relationships

QuantityV1 · φV2 · √2
Cone heightφ·D√2·D
Tetrahedron height(√2 + φ)·D2√2·D = √8·D
Tetrahedron edge(√3 + φ·√6/2)·D2√3·D = √12·D
Tetrahedron centre, above the floor
(= distance from the centre to each face)
(√2 + φ)·D/4√2·D/2
Crystal (coil centre), above the floorφ·D/2√2·D/2
Crystal minus tetrahedron centre(φ − √2)·D/4 ≈ 1.89 cm0
Cone side angle from the axistan = 1/(2φ) · 17.17°tan = 1/(2√2) · 19.47°
Tetrahedron face angle from the axisarcsin(1/3) · 19.47°arcsin(1/3) · 19.47°
Angle between face perpendicularsarccos(−1/3) · 109.47°109.47°

The empty space: cone bases to the tetrahedron

How far each cone base ring sits from the tetrahedron's edges, corners and walls. In each formula, H is the cone height and D the base diameter.

GapExactV1 · φV2 · √2
Bottom ring → base edge (along the floor)H / (2√2)21.17 cm18.50 cm = D/2
Bottom ring → sloping wall (perpendicular)H / 319.96 cm17.44 cm
Bottom ring → base cornerD/2 + H/√260.83 cm55.50 cm = 3D/2
Top ring → sloping walls0 (by design)0 cm · touching0 cm · touching
Top ring → vertical edge (same height)D / 218.50 cm18.50 cm
Top ring → vertical edge (perpendicular)D / √615.11 cm15.11 cm
Top ring → apex√2·D52.33 cm52.33 cm

These are exact values for the ideal geometry. In the 3D model, which includes the 0.8 mm wire, the measured gaps match to within 0.3 cm.

Finding 01

The tetrahedron is the two ratios added together. Its height is (√2 + φ)·D. The coil fills the lower φ·D, and the space above it is always exactly √2·D, whatever the cone shape. That top section is a smaller tetrahedron, and the cone it would hold is exactly the V2 cone.

Finding 02

With φ cones, the crystal misses the centre. In V1 the tetrahedron's true centre, where the four face perpendiculars meet, sits (φ − √2)·D/4 ≈ 1.89 cm below the crystal. That is just under the 20 mm crystal, inside the lower rod. The whole offset comes from the difference between φ (1.618) and √2 (1.414).

Finding 03

The bottom gap is always one third of the cone height. The perpendicular distance from the bottom ring to the sloping walls is exactly H/3 in any design that fits this way. The gaps around the top ring are fixed by the tetrahedron alone: D/2 sideways to each edge, D/√6 straight to each edge, and √2·D to the apex. They are the same in both versions.

Where the centres are

Two different centres matter here, and they are easy to mix up:

In V1 the two centres are 1.89 cm apart, with the crystal higher. In V2 they are the same point.

Finding 04

Only √2 cones put the crystal at the centre. For the coil's centre to coincide with the tetrahedron's centre, the cone height must be exactly √2·D, giving an apex angle of 38.94°. Then every measurement becomes a whole number times a square root of D:

Finding 05

The √2 version repeats itself. The empty space above a √2 coil is a smaller tetrahedron with exactly the same proportions. A √2 coil that fits it is exactly half the size (18.5 cm across), and its lower tip touches the upper tip of the coil below. Repeat it, and each coil is half the one beneath, climbing toward the apex. Their heights add up as H + H/2 + H/4 + … = 2H, which is exactly the tetrahedron's height, so the tower of coils reaches the apex. With φ cones the space above holds a coil about 0.47 times the size, and the pattern does not repeat cleanly.

A regular tetrahedron's own proportions are built from √2, √3, √6 and the angle arcsin(1/3). A shape that fits it in every respect therefore tends to take on those roots. The golden ratio does not come from tetrahedral geometry, so φ cones fit tightly but always leave a small mismatch. Which version is right for the device is an open question that only testing can answer.

The cone family: 78°, 19.5° and φ

Bashar refers to cones of 19.5° and 78°, and describes the 19.5° cone through 33⅓. Worked out exactly, three cones belong together. They differ only in one number: the cone's height divided by its base diameter.

Cone78° · 1/φ√2 · 19.5°Golden φ
Height ÷ base diameter1/φ = 0.618√2 = 1.414φ = 1.618
Side angle from the axis38.97°19.47° (sin = 1/3)17.17°
Full tip angle77.95°38.94°34.34°
Unrolled: slice of a full circle62.9% (226.4°)33⅓% exactly (120°)29.5% (106.3°)
Base radius ÷ slanted side0.6291/3 exactly0.295
Fitting tetrahedron height (D = 37 cm)75.2 cm104.7 cm112.2 cm
Crystal vs the tetrahedron's true centre7.36 cm below0, exactly centred1.89 cm above
Offset formulaoffset = (height ÷ diameter − √2) · D / 4

Explore: roll a slice of a circle into a cone

Cut a slice out of a circle and roll it up: the circle's radius becomes the cone's slanted side, and the slice's curved edge becomes its base. The bigger the slice, the wider the cone.

Slice of the circle
The flat circle and the slice you cut out
Rolled up: the cone it makes
Side angle from the axis
Full tip angle
Height ÷ base diameter
Base radius ÷ slanted side

How the three cones relate

The 33⅓ cone

Roll exactly one third of a circle and you get the √2 cone. Its base radius is exactly one third of its slanted side, so its sides lean at the angle whose sine is 1/3: 19.47°, the 19.5° tetrahedral angle. In practice you can make it without measuring any angle: cut a disc into three equal slices and roll one.

Halving: 78° → 39° → 19.5°

Half of the 78° cone's tip angle (77.95° ÷ 2 = 38.97°) is almost exactly the √2 cone's tip angle (38.94°, a 0.03° difference). Half of the √2 cone's tip angle is exactly 19.47°. The √2 cone is the middle step of the sequence.

Mirror images: φ and 1/φ

The golden cone is φ times as tall as it is wide; the 78° cone is the same proportion turned on its side, φ times as wide as it is tall. The two ratios differ by exactly one: φ − 1/φ = 1.

The centre between them

In a fitting tetrahedron, the crystal sits below the true centre with the 78° cone (7.36 cm) and above it with the golden cone (1.89 cm). The √2 cone, between the two, is the only one that lands exactly on it. All three follow the same rule: offset = (height ÷ diameter − √2) · D/4.

Switch the 3D model above to 78° · 1/φ to see the flat cone in its own tetrahedron. Geometry here is exact; what these cones do physically is for experiment to show.

The core

The core on its own: a 20 mm quartz sphere on a 5 mm copper rod, a flat copper ring, and a polycarbonate disc with 21 and 34 golden-spiral copper inlays meeting an outer copper wire ring.
The core at the centre of the coil. In this image the coil and tetrahedron are hidden.

Golden in two directions

In V1 the golden ratio runs through the device twice. Along the axis, each cone is φ times as tall as it is wide. Across the disc, every spiral widens by φ each quarter turn, and the two sets, 21 and 34, are neighbouring Fibonacci numbers whose ratio (1.619…) approaches φ. In V2 only the axis changes to √2; the disc stays golden.

Three motions: the design idea

Each shape turns rotation into another kind of motion. This is plain geometry:

Both shapes also concentrate the field. A smaller loop concentrates its field more tightly, so each cone's field is strongest toward its tip. On the disc, the spirals crowd together and cross more and more often toward the centre. The working idea, not yet measured, is that these gradients drive flow: axially through the cones (up one, down the other) and radially across the disc. Together they would form a spherical pulse of expansion and contraction around the centre, following the rhythm of the alternating current that drives it.

Both versions

V1 and V2 together at true relative scale, both cut open, with cyan reference lines showing each tetrahedron's centre.
V1 (left) and V2 (right) at true relative scale, with the coils cut away and the face-to-centre reference lines shown.

Notes for builders